Simplifying Algebraic Expressions
This lesson explains simplifying algebraic expressions step by step using clear GCSE examples.
What are algebraic expressions?
Algebraic expressions are combinations of numbers, letters and operations. The letters represent unknown values, while the numbers are constants.
For example:
In this lesson, we will learn how to simplify expressions by collecting like terms — one of the most important algebra skills at GCSE.
Example Question:
We will work through this step by step:
Simplify the expression:
Exam Tip
Always group the same types of terms together before combining them.
Look for:
- Terms with the same letter
- Terms with the same power
- Numbers (constants)
Remember: You can only combine like terms.
Method — Simplifying Algebraic Expressions
We simplify expressions by collecting like terms. This means combining multiples of the same letter-and-power part. Keep the sign with each term.
Follow these steps:
- Identify like terms
Terms are alike if they have the same letters raised to the same powers. - Rearrange the expression
Put like terms next to each other. - Combine the coefficients
Add or subtract the numbers in front of the letters. - Combine constant terms
Add or subtract any standalone numbers.
Worked Example
Simplify:
Step 1: Identify like terms
Like terms are:
and (both contain )
and (both are numbers)
Step 2: Rearrange the expression
Step 3: Combine terms
Expression becomes:
Step 4: Combine constants
Final answer:
Always write your answer in its simplest form.
Check your solution (important habit)
Pick a value for to check both expressions give the same result.
Let
Original expression:
Simplified expression:
Both expressions give the same result for x = 1. Substitution is a useful check for mistakes, but matching at one value does not prove that two expressions are equal for every value of x. Here, collecting like terms using the rules of algebra establishes the simplification.
Products, powers and algebraic reasoning
Worked example — More than one kind of term
Simplify 4a² + 3ab − a² + 2ab − 5.
Group matching letter-and-power parts: (4 − 1)a² + (3 + 2)ab − 5.
3a² + 5ab − 5. The a² and ab terms cannot be combined.
Worked example — Multiply and divide terms
In 3a × 4ab, multiply the numbers and then the letters.
3 × 4 × a × a × b = 12a²b.
For 18x³ ÷ 6x, divide the coefficients and cancel one factor x: 18 ÷ 6 = 3 and x³ ÷ x = x².
The result is 3x², provided x ≠ 0. The symbol ≠ means “not equal to”; the original divisor cannot be zero.
Addition works differently: 3a + 4a = 7a, not 7a².
Worked example — Apply index laws
A positive whole-number index tells us how many equal factors are multiplied. x² × x³ has five factors x, so it is x⁵.
x⁵ ÷ x² = x³ for x ≠ 0, because two factors cancel.
(2x²)³ = (2x²)(2x²)(2x²) = 8x⁶. Cube the coefficient as well as the power of x.
For a non-zero base, x⁰ = 1: x³ ÷ x³ is both 1 and x⁰.
Negative integer powers — Foundation & Higher
For x ≠ 0, x⁻² means 1/x². A negative index does not mean a negative answer.
x³ × x⁻⁵ = x⁻² = 1/x².
Higher extension — Fractional powers
For positive x, x1/2 means √x. Thus x1/2 × x = x3/2: add ½ and 1.
Use the same-base rules only when the bases match. They do not turn x² × y³ into a single power of x. For the numerical index laws and root methods, see Powers and Roots.
Worked example — Show two expressions are equivalent
Show that 5x + 4 − 2x and 3(x + 1) + 1 have equal values for every x.
Collect terms in the first: 5x − 2x + 4 = 3x + 4.
Expand the second: 3x + 3 + 1 = 3x + 4.
Both simplify to the same expression. This establishes an identity; checking just one number would not.
Higher extension — A short algebraic proof
Prove that the sum of three consecutive integers is a multiple of 3. Let n be any integer. The next two integers are n + 1 and n + 2.
n + (n + 1) + (n + 2) = 3n + 3 = 3(n + 1).
Since n + 1 is an integer, this is 3 times an integer. That proves the claim for every starting integer.
A few numerical examples can suggest a pattern, but they cannot prove a statement about all integers. Continue to Expanding Brackets for the main algebraic-proof method.
Think Like a Mathematician
Simplifying makes expressions easier to work with and helps reveal structure.
For example, the expression:
can be simplified to:
This form is easier to evaluate, graph or substitute into equations.
Common mistakes to avoid
- Combining unlike terms (for example, cannot be simplified)
- Forgetting negative signs
- Mixing variables and constants incorrectly
- Losing a sign when rearranging terms
Most errors occur when students rush and combine terms incorrectly.
Try one yourself
Simplify the following expression:
Hint: Rearrange first so like terms are together.
Collect like terms, keeping each term’s sign.
4x + 9 − 2x + 3 = 4x − 2x + 9 + 3
4x − 2x = 2x and 9 + 3 = 12.
Answer: 2x + 12
As a check, let x = 2: the original gives 8 + 9 − 4 + 3 = 16, and the simplified expression gives 4 + 12 = 16.
More practice — expressions and reasoning
1. Simplify 6x² − 2x + x² + 5x − 4.
Combine the squared terms: 6x² + x² = 7x².
Combine the x terms: −2x + 5x = 3x. Keep the constant −4.
7x² + 3x − 4.
2. Simplify 5a × 2ab and 20y⁴ ÷ 5y².
5 × 2 = 10 and a × a × b = a²b, giving 10a²b.
20 ÷ 5 = 4; subtract indices 4 − 2 = 2, giving 4y², for y ≠ 0.
3. Simplify (3x²)² and x³ × x⁴.
(3x²)² = 3² × x⁴ = 9x⁴.
x³ × x⁴ = x^(3 + 4) = x⁷.
4. Show that 2(3x + 1) − x is equivalent to 5x + 2.
Expand: 6x + 2 − x.
Collect x terms: 5x + 2. Each algebraic step preserves the value for every x.
5. Simplify x² ÷ x⁵ for x ≠ 0, using a positive index in your answer.
Subtract the indices: x^(2 − 5) = x⁻³.
A negative index gives a reciprocal: 1/x³.
6. Higher: prove that the sum of two consecutive odd integers is divisible by 4.
Let n be an integer. Consecutive odd integers can be written 2n + 1 and 2n + 3.
Their sum is 4n + 4 = 4(n + 1).
Because n + 1 is an integer, the sum is divisible by 4.
Frequently Asked Questions
What are like terms?
Like terms have exactly the same variables raised to the same powers.
For example:
and are like terms
and are like terms
and are NOT like terms
Why can we add and but not and ?
Because and represent quantities of , while is just a number with no variable.
